Posted by mushibwe lameck c on Monday, June 13, 2011 at 6:11am.
Your formula for bornite in the reaction is incorrect. You forgot the 3 after Cu
The molar mass of Cu3FeS3 is 342.53
The molar mass of Cu is 63.55
In a completed reaction. 2 moles (684.06 g) of Cu3FeS3 would produce 6 moles (381.30 g) of Cu. That means 55.7% of the bornite mass would become Cu. With a 75.6% yield, that ratio becomes 0.756 x 0.557 or 42.4%
From 3.88 metric tons of bornite, 1.64 tons of pure copper would be produced.
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