Posted by **caleb** on Sunday, June 12, 2011 at 9:55pm.

find the exact solution algebraically and check it by substituting into the orginal equation.

1. 36(1/3)^x/5=4

2. 32(1/4)^x/3=2

- pre calc -
**Reiny**, Sunday, June 12, 2011 at 11:44pm
the way you typed it .....

36(1/3)^x = 20

(1/3)^x = .5555555..

x ln(1/3) = .55555..

x = .535 appr.

what you probably meant:

36(1/3)^(x/5) = 4

(1/3)^(x/5) = .111111..

x/5 = ln .111111 / ln(1/3)

x = 10

in the second, you probably have the same typo, and I will assume:

32(1/4)^(x/3) = 2

here is another way to do this:

notice that all factors are powers of 2, so ...

(2^5)(2^-2)^(x/3) = 2^1

2^(-2x/3) = 2^-4

-2x/3 = -4

x = 6

we could have done the first the same way, after dividing both sides by 32 to get

(1/3)^(x/5) = 1/9 = (1/3)^2

so x/5 = 2

x = 10

## Answer this Question

## Related Questions

- pre calc - find exact solution algebraically and check it by substituting into ...
- Pre Calc - 7. The Sandusky Little League uses a baseball throwing machine to ...
- Pre-Calc - Determine the solution. x^2=|x|algebraically I have no idea how to ...
- pre-calculus - solve the logarithmic equation. be sure to reject any value of x ...
- calculus - solve the logarithmic equation. be sure to reject any value of x that...
- pre calculous - solve each equation algebraically and check it by substituing ...
- Pre-Calc - An open box with a volume of 1500cm^3 is to be constructed by taking ...
- Pre Calc 12 - Four consecutive integers have a product of 360 Find the integers ...
- Pre-Calc - Find the zeros of the function algebraically. Show all work. f(x)=x^2...
- Pre-Calc - Find the zeros of the function algebraically. Show all work. f(x)=x^2...