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Posted by **Wykeena** on Sunday, June 12, 2011 at 6:33pm.

Find the peak's elevation

- Physics -
**drwls**, Sunday, June 12, 2011 at 6:37pmWhat are the units of your 28.5 number? And of your elevation? And the 3.0 ? Is the latter degrees?

You can't do physics without including dimensions with your numbers.

This appears to be basically a trig problem. Use the definition of the tangent of an angle.

- Physics -
**Wykeena**, Sunday, June 12, 2011 at 6:55pmSorry it is 28.5m horizontally from the peak. You see a peak at 3.0 degrees, and the current eleevation is 1630 meters.

- Physics -
**drwls**, Sunday, June 12, 2011 at 7:02pmElevation (in meters) = 1630 + 28,500 tan 3.0

= 3124 m

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