what is the morality of a solution made by dissolving 1.00g of sodium hydroxide, NaOH in 100 mL of water
Hmm -- A chemical solution is not capable of morality.
Do you mean molarity?
The "morality" you mentioned is likely a typo. I assume you meant "molarity" instead. Molarity is a measure of the concentration of a solute (in this case, sodium hydroxide) in a solution. To calculate the molarity, we need to know the number of moles of sodium hydroxide and the volume of the solution.
To calculate the molarity, we need to follow these steps:
Step 1: Calculate the number of moles of sodium hydroxide (NaOH)
To find the number of moles, we use the formula:
number of moles = mass / molar mass
The molar mass of sodium hydroxide (NaOH) is calculated by summing up the atomic masses of its constituent elements:
molar mass of NaOH = atomic mass of Na + atomic mass of O + atomic mass of H
The atomic mass of sodium (Na) is approximately 22.99 grams/mol, the atomic mass of oxygen (O) is 16.00 grams/mol, and the atomic mass of hydrogen (H) is approximately 1.01 grams/mol.
Step 2: Calculate the molarity
Molarity (M) is defined as the number of moles of solute per liter of solution. Since we have the volume in milliliters (mL), we need to convert it to liters (L) by dividing by 1000.
Molarity (M) = moles of solute / volume of solution (in liters)
By plugging in the values, we can calculate the molarity.
Let's do the calculations together:
Step 1: Calculate the number of moles of NaOH:
mass = 1.00 g
molar mass NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.00 g/mol (approximately)
moles of NaOH = mass / molar mass = 1.00 g / 39.00 g/mol ≈ 0.0256 mol
Step 2: Calculate the molarity (M):
volume of solution = 100 mL = 100 / 1000 = 0.1 L
Molarity (M) = moles of NaOH / volume of solution
M = 0.0256 mol / 0.1 L ≈ 0.256 M
Therefore, the molarity of the sodium hydroxide solution prepared by dissolving 1.00 g of NaOH in 100 mL of water is approximately 0.256 M.