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Algebra

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Train a is traveling @ 60 miles per hour. Train b is traveling @ 80 miles per hour. A arrives @ 9:25 am and b arrives @ 9:40 am what ime will train b catch up to train a?

  • Algebra - ,

    Do you not mean departs, not arrives? If so:
    a travels 40-25 = 15 minutes longer than b

    if b travels for t minutes, then a travels for t+15 minutes
    a speed = 60/60 = 1 miles/min
    b speed = 80/60 = 4/3 miles/min
    distances are the same so
    1(t+15) = (4/3) t
    3 t + 45 = 4 t
    t = 45 minutes
    so time = 9:40 + 45 = 10:25 am

  • Algebra - ,

    9:40am - 9:25am = 15min.

    15min/60min/h = 0.25h.

    When train "B" catches up,the distance
    traveled will be the same for each train:

    d1 = d2.
    60(t+0.25) = 80t,
    60t + 15 = 80t,
    t = 0.75h = 45min = Time required for
    "B" to catch-up.
    Time = 9:40 + 45 = 10:25am.

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