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August 30, 2014

August 30, 2014

Posted by **David** on Sunday, June 12, 2011 at 5:08pm.

- Algebra -
**Damon**, Sunday, June 12, 2011 at 5:25pmDo you not mean departs, not arrives? If so:

a travels 40-25 = 15 minutes longer than b

if b travels for t minutes, then a travels for t+15 minutes

a speed = 60/60 = 1 miles/min

b speed = 80/60 = 4/3 miles/min

distances are the same so

1(t+15) = (4/3) t

3 t + 45 = 4 t

t = 45 minutes

so time = 9:40 + 45 = 10:25 am

- Algebra -
**Henry**, Sunday, June 12, 2011 at 7:54pm9:40am - 9:25am = 15min.

15min/60min/h = 0.25h.

When train "B" catches up,the distance

traveled will be the same for each train:

d1 = d2.

60(t+0.25) = 80t,

60t + 15 = 80t,

t = 0.75h = 45min = Time required for

"B" to catch-up.

Time = 9:40 + 45 = 10:25am.

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