Posted by cal on .
Andrew factored the expression 28x©ø6x©÷10x as 2x(14x©ø3x©÷5x) . But when Melissa applied the distributive law and multiplied out 2x(14x©ø3x©÷5x), she got 28x©ù6x©ø10x©÷; thus, Andrew¡¯s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state.

algebra 
Damon,
I suppose this is
28 x^3  6 x^2 10 x
= 2 x (14 x^2  3 x  5) not 5 x