A 990 kg car is pulling a 300 kg trailer. Together, the car and trailer have an acceleration of 2.13 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following (including sign).

(a) the net force on the car
(b) the net force on the trailer
(c) the force exerted by the trailer on the car
(d) the resultant force exerted by the car on the road.
magnitude N
direction ° measured from the left of vertically downwards

F=ma on the car, m=990+300

on the trailer, m=300

considering we use Newtons second law, we also have to logically conclude that we are individually find each object's net force. Therefore we neglect the other mass i.e. we plug in Newtons second law for the car Fnet = (990)(2.15), considering we are isolating the objects we ignore the second mass: hence the answer for part A is

~= 2128.5. Now part B will be the same thing using the same logic we did for part A. In part D you tak into account both masses therefore in your answer you add the masses. Fnet = 1290*2.15... Lol Idk how to solve c but A,B and D that is how you solve it.

To determine the net force on the car and trailer, we can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.

(a) The net force on the car can be calculated using the formula:

net force on car = mass of car * acceleration

Given that the mass of the car is 990 kg and the acceleration is 2.13 m/s², we can calculate:

net force on car = 990 kg * 2.13 m/s² = 2102.7 N (forward)

Therefore, the net force on the car is 2102.7 N in the forward direction.

(b) The net force on the trailer can be calculated using the same formula:

net force on trailer = mass of trailer * acceleration

Given that the mass of the trailer is 300 kg and the acceleration is 2.13 m/s², we can calculate:

net force on trailer = 300 kg * 2.13 m/s² = 639 N (forward)

Therefore, the net force on the trailer is 639 N in the forward direction.

(c) To determine the force exerted by the trailer on the car, we can consider it as an external force acting on the car. Since there are no other horizontal external forces acting on the system, the force exerted by the trailer on the car will be equal in magnitude but opposite in direction to the net force on the car.

Therefore, the force exerted by the trailer on the car is 2102.7 N (backward).

(d) To calculate the resultant force exerted by the car on the road, we need to take into account the force exerted by the trailer on the car and the weight of the car.

The weight of the car can be calculated using the formula:

weight = mass of car * gravitational acceleration

Assuming the gravitational acceleration is approximately 9.8 m/s²:

weight = 990 kg * 9.8 m/s² = 9702 N (downward)

Since the car and trailer are accelerating forward together, the resultant force exerted by the car on the road will be the sum of the net force on the car and the weight of the car:

resultant force on the road = net force on car + weight of car

resultant force on the road = 2102.7 N + 9702 N = 11804.7 N (downward)

Therefore, the resultant force exerted by the car on the road is 11804.7 N downward.