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December 20, 2014

December 20, 2014

Posted by **Mike** on Saturday, June 11, 2011 at 10:21am.

give the value of:

Tan(Arctan x+1/x-1+Arctan x-1/x)

- Trig -
**Reiny**, Saturday, June 11, 2011 at 10:52amlet arctan((x+1)/(x-1)) = A or tanA = (x+1)/(x-1)

let arctan((x-1)/x) = B or tanB = (x-1)/x

then Tan(Arctan x+1/x-1+Arctan x-1/x)

= tan(A+B)

= (tanA + tanB)/(1-tanAtanB)

= [ (x+1)/(x-1) + (x-1)/x ] / [1 - (x+1)/(x-1)(x-1)/x ]

= ....

= (2x^2 - x + 1)/(1-x)

check my algebra

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