Posted by Anonymous on Saturday, June 11, 2011 at 3:34am.
first, we represent the unknowns using variables.
let x = outfits that Jane packed
let x-1 = outfits that Charlie packed
let 2x-5 = outfits that Loretta packed
since "limited to a total of 24 outfits", it means that the maximum number of outfits is 24:
x + (x-1) + (2x-5) <= 24
note: <= means less than or equal to
solving,
4x - 6 <= 24
4x <= 30
x <= 7.5
but since outfits cannot be a decimal/fraction, we take
x = 7 (the max number of outfit that Jane can pack)
and thus,
x-1 = 6 (max number of outfit that Charlie can pack)
2x-5 = 9 (max number of outfit that Loretta can pack)
hope this helps~ :)
If Jane packs x "outfits", the total number packed is
x + (x-1) + (2x -5) =or< 25
4x -6 =or< 25
4x <or= 31, and x must be an integer
x <or= 7 is Jane's number
6 is Charlie's maximum
9 is Loretta's maximum
They will not use up the available space if they stick to the rules relative to each other. There is room for two more outfits, unless I made a mistake along the way. See what you get
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