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March 6, 2015

March 6, 2015

Posted by **Anonymous** on Saturday, June 11, 2011 at 3:34am.

- Translate the following situation into an inequali -
**Jai**, Saturday, June 11, 2011 at 3:46amfirst, we represent the unknowns using variables.

let x = outfits that Jane packed

let x-1 = outfits that Charlie packed

let 2x-5 = outfits that Loretta packed

since "limited to a total of 24 outfits", it means that the maximum number of outfits is 24:

x + (x-1) + (2x-5) <= 24

note: <= means less than or equal to

solving,

4x - 6 <= 24

4x <= 30

x <= 7.5

but since outfits cannot be a decimal/fraction, we take

x = 7 (the max number of outfit that Jane can pack)

and thus,

x-1 = 6 (max number of outfit that Charlie can pack)

2x-5 = 9 (max number of outfit that Loretta can pack)

hope this helps~ :)

- Translate the following situation into an inequali -
**drwls**, Saturday, June 11, 2011 at 3:54amIf Jane packs x "outfits", the total number packed is

x + (x-1) + (2x -5) =or< 25

4x -6 =or< 25

4x <or= 31, and x must be an integer

x <or= 7 is Jane's number

6 is Charlie's maximum

9 is Loretta's maximum

They will not use up the available space if they stick to the rules relative to each other. There is room for two more outfits, unless I made a mistake along the way. See what you get

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