Posted by ashley on Saturday, June 11, 2011 at 1:48am.
At t = 1.6 sec., the man has jogged 1.76m.
From that point on, the dog closes in on the man at the speed of 3.8 - 1.1 = 2.7m/s.
The time for the dog to catch the man is therefore t = 1.76/2.7 = .65s.
The man will have jogged .717m further for a total distance of 2.477m.
The dog will have traveled .65(3.8) = 2.477m.
Thanks! I have one more question: how did you get the .717m for the man?
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