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A man jogs at a spee of 1.1 m/s. His dog waits 1.6s and then takes off running at a speed of 3.8 m/s to catch up with the man.

How far will they each have traveled when the dog catches up with the man?Answer in units of m

  • physics - ,

    At t = 1.6 sec., the man has jogged 1.76m.

    From that point on, the dog closes in on the man at the speed of 3.8 - 1.1 = 2.7m/s.

    The time for the dog to catch the man is therefore t = 1.76/2.7 = .65s.

    The man will have jogged .717m further for a total distance of 2.477m.

    The dog will have traveled .65(3.8) = 2.477m.

  • physics - ,

    Thanks! I have one more question: how did you get the .717m for the man?

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