Posted by ashley on Saturday, June 11, 2011 at 1:41am.
Are we to assume that they started at the same time?
3.9999 cm/s might as well be called 4.0 cm/s, since there are only two significant figures for other numbers.
t1 = 70cm / 5.7cm/s = 12.88s = the 1st
ants' time.
d2=4cm/s * 12.88s = 49.12cm = Distance the 2nd ant ran during the 12.88s.
d = 70 - 49.12 = 20.88cm = Distance behind.
Related Questions
Physics - Two ants race across a table 65 cm long. One travels at 5.76 cm/s and ...
physics - Two ants race across a table 63 cm long. One travels at 5.14 cm/s and ...
Physics - Two ants race across a table 58cm long. One travels at 4.8 cm/s and ...
physics - 2 ants cross a counter 54cm long, one travels at 16 meters per second...
physics - 2 ants cross a counter 54cm long, one travels at 16 meters per second...
Physics - please check: An ant on a picnic table travels 3.0 * 10^1 cm eastward...
physics - Two long parallel wires carry currents of 10 A in opposite directions...
Physics - An ant on a picnic table travels 40 cm eastward, then 25 cm northward...
Physics - An ant on a picnic table travels 40 cm eastward, then 25 cm northward...
physics - A tortoise can run with a speed of 11.5 cm/s, and a hare can run 21.4 ...
For Further Reading
