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given vectors ,
Vector a= 2i + 3j, then the angle between vector a and y axis is?
Plz solve

  • science(physics) -

    cosine theta = (a*i)/|a|
    |a| is the magnitude of the a vector,
    which is sqrt13 = 3.6056
    a*1 is the dot product of a and the i vector, which is 2.

    Therefore cos theta = 2/3.6056 = 0.5547
    theta = 56.3 degrees

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