the sum of three forces f1=100n, f2=80n, f3=60n acting on a particle is zero.

The angle between f1 and f2 is:

Please solve

|F1+F2|=|F3|

Squaring both sides
|F1+F2|²=|F3|²
=>cos(theta) =37°

To find the angle between two forces, we can use the concept of vectors and vector addition.

Given that the sum of the three forces is zero, we can express this as a vector equation:
f1 + f2 + f3 = 0

Let's consider the vector components of each force. Assuming the forces are acting on different directions, we can break down each force into its x and y components.

f1 = (f1x, f1y)
f2 = (f2x, f2y)
f3 = (f3x, f3y)

Since the forces add up to zero, their x and y components must also add up to zero individually:
f1x + f2x + f3x = 0 (Equation 1)
f1y + f2y + f3y = 0 (Equation 2)

Given:
f1 = 100N
f2 = 80N
f3 = 60N

We want to find the angle between f1 and f2. Let's denote this angle as θ.

To find the angle, we can use the dot product of the two vectors:

f1 · f2 = ||f1|| ||f2|| cos(θ)
Here, ||f1|| and ||f2|| represent the magnitudes of the respective vectors f1 and f2.

Let's calculate the magnitudes of the forces:
||f1|| = √(f1x^2 + f1y^2)
||f2|| = √(f2x^2 + f2y^2)

Now, let's solve for the dot product of f1 and f2:
f1 · f2 = f1x * f2x + f1y * f2y

To find the angle θ, we substitute the values into the equation and calculate:

cos(θ) = (f1x * f2x + f1y * f2y) / (√(f1x^2 + f1y^2) * √(f2x^2 + f2y^2))

Finally, we can find the angle θ by taking the inverse cosine (arccos) of the result obtained above.

Keep in mind that we still need to determine the x and y components of each force in order to find the angle. Please provide any additional information or clarify if the forces are acting in specific directions.

To find the angle between f1 and f2, we can use the concept of vector addition. Since the sum of three forces is zero, we can write it as:

f1 + f2 + f3 = 0

Given that f1 = 100 N, f2 = 80 N, and f3 = 60 N, we can substitute these values into the equation:

100 N + 80 N + 60 N = 0

This equation simplifies to:

240 N = 0

Since this equation is not possible (forces cannot add up to zero), there seems to be some mistake in the given information or calculations.

Please double-check the given forces or provide additional information if needed.

you don't say what n is, but it looks like all three vectors are in the same direction. It would not be possible for the sum of all three to be zero, since they are all positive