Zinc metal reacts with hydrochloric acid to produce hydrogen gas according to the equation below. What volume of hydrogen at STP is released when 15.1 grams of zinc react at STP?

Zn(s) + 2HCl(aq) �¨ ZnCl2(aq) + H2(g)

Just follow the example problem on the link.

http://www.jiskha.com/science/chemistry/stoichiometry.html

A) HCL B)1.35G

To find the volume of hydrogen gas released when 15.1 grams of zinc react, we need to use stoichiometry and the ideal gas law.

Step 1: Convert grams of zinc to moles.
The molar mass of zinc (Zn) is 65.38 g/mol.
Moles of zinc = mass of zinc / molar mass of zinc
Moles of zinc = 15.1 g / 65.38 g/mol
Moles of zinc = 0.231 mol

Step 2: Use the stoichiometry of the balanced equation to find moles of hydrogen gas produced.
From the balanced equation, we see that 1 mole of zinc reacts with 1 mole of hydrogen gas.
Moles of hydrogen gas = moles of zinc

Step 3: Convert moles of hydrogen gas to volume at STP.
The molar volume of any gas at STP is 22.4 L/mol.
Volume of hydrogen gas = moles of hydrogen gas * molar volume at STP
Volume of hydrogen gas = 0.231 mol * 22.4 L/mol
Volume of hydrogen gas = 5.16 L

Therefore, when 15.1 grams of zinc react at STP, 5.16 liters of hydrogen gas is released.

To find the volume of hydrogen gas released when 15.1 grams of zinc react with hydrochloric acid at STP (Standard Temperature and Pressure), we need to use the ideal gas law.

The idea gas law equation is: PV = nRT

Where:
P = pressure (in atmospheres)
V = volume (in liters)
n = number of moles
R = gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)

First, we need to calculate the number of moles of zinc using its molar mass. The molar mass of zinc (Zn) is 65.38 g/mol.

Number of moles of zinc = 15.1 g / 65.38 g/mol = 0.2311 mol

According to the balanced chemical equation, for every 1 mole of zinc that reacts, 1 mole of hydrogen gas is produced. Therefore, the number of moles of hydrogen gas produced is also 0.2311 mol.

Next, we convert the temperature to Kelvin. STP is defined as 273 Kelvin.

Substituting the values into the ideal gas law equation: PV = nRT

Using STP conditions:
P = 1 atmosphere
V = unknown (what we are trying to find)
n = 0.2311 mol
R = 0.0821 L·atm/mol·K
T = 273 Kelvin

We can rearrange the equation to solve for V:
V = (nRT) / P

Plugging in the values, we get:
V = (0.2311 mol * 0.0821 L·atm/mol·K * 273 Kelvin) / 1 atmosphere

V = 5.98 liters

Therefore, approximately 5.98 liters of hydrogen gas is released when 15.1 grams of zinc react with hydrochloric acid at STP.