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April 20, 2014

April 20, 2014

Posted by **Linsey** on Thursday, June 9, 2011 at 11:24am.

- Cupler -
**MathMate**, Thursday, June 9, 2011 at 12:02pmMethod 1 using Algebra:

Let x=volume of 1% milk in gallons

then (5-x)=volume of 4% milk

5*2%=x*1%+(5-x)*4%

Solve for x:

10=x+20-4x

3x=10

x=3 1/3 gal. (1% milk)

5- 3 1/3 = 1 2/3 gal. (4% milk).

Method 2 (mental calculations)

Mentally put the 1% and 4% on a linear scale as follows:

1%..................................4%

The target percentage is 2%:

1%......**2%**..............4%

Take the difference:

.....1.............2.........

these are the ratio of the**4%**and**1%**milk respectively (note the inversion of position), i.e.

4% milk : 1% milk = 1:2

Therefore

volume of 4% = 5*1/(1+2)=1 2/3 gal

volume of 1% = 5*2/(1+2)=3 1/3 gal.

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