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December 22, 2014

December 22, 2014

Posted by **Greg** on Thursday, June 9, 2011 at 1:03am.

Loga(x+3) + Loga(x-3) = 3

I don't know if I'm typing this correctly the a is the base.

So, I'm thinking,

Loga((x+3)(x-3)) = 3

(x+3)(x-3) = 3^a

x^2 - 9 = 3^a,

x^2 = 3^a + 9

x = sqrt(3^a + 9)

but now I'm stuck, I don't know how to proceed. I don't know if this is the answer...

- Math - Properties of Logarithm -
**drwls**, Thursday, June 9, 2011 at 2:14amYou are mixing up 3^a and a^3

The base of the logarithm (a) is what gwets raised to a power (3, in this case).

loga[(x+3)(x-3)] = 3

loga(x^2-9) = 3

a^3 = x^2-9

x = sqrt(a^3 +9)

- Math - Properties of Logarithm -
**Greg**, Thursday, June 9, 2011 at 2:42amThanks... got it...

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