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December 21, 2014

December 21, 2014

Posted by **Hailey** on Wednesday, June 8, 2011 at 8:51pm.

- math -
**Mgraph**, Wednesday, June 8, 2011 at 9:23pm=(16*x^2*y*4*x^5*y^2*z)^1/3=

=(64*x^7*y^6*z)^1/3=

=64^1/3*(x^7)^1/3*(y^6)^1/3*z^1/3=

4*x^(7/3)*y^2*z^1/3

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