Thursday
March 23, 2017

Post a New Question

Posted by on Wednesday, June 8, 2011 at 7:24pm.

With the initial concentrations of [SCN]= 0.0005 M, [Fe3+]= 0.000698M, and [Fe(SCN)2+]=0.000M, determine the value of k if the [Fe(SCN)2+] at equilibrium is 0.0000866M.

Fe3+(aq) + SCN (aq) = Fe(SCN)2+ (aq)

  • Chemistry - , Wednesday, June 8, 2011 at 7:48pm

    ..............Fe^3+ + SCN^-==>FeSCN^2+
    initial.....0.0005...0.000698...0
    change.........-x......-x.......+x
    equil... 0.0005-x..0.000698-x...8.66E-5

    so x must be 8.66E-5 which allows you to determine SCN^- and Fe(III) at equil then plug into the Kc expression to determine k.

  • Chemistry - , Wednesday, May 6, 2015 at 4:07am

    210

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question