Posted by **Liz** on Wednesday, June 8, 2011 at 3:00pm.

A car passes by a certain point at time t = 0 hours heading east at 40 miles per hour. At t = 1 hour another car passes by the same point heading north at 50 miles per hour. What is the functiuonthat equals the distance between the two cars?

- Calculus -
**bobpursley**, Wednesday, June 8, 2011 at 3:05pm
distance= sqrt[(40t)^2+(50(t-1))^2 ]

check my thinking.

- Calculus -
**Liz**, Wednesday, June 8, 2011 at 3:21pm
The answer has to be one of the following:

a. L=90t-50

b. L= sqrt(4100t)

c. L= sqrt(4100t^2 +5000t +2500)

d. L= sqrt(4100t^2-5000t + 2500)

e. L= sqrt(90t-50)

- Calculus -
**bobpursley**, Wednesday, June 8, 2011 at 3:35pm
And, it is one of those. Can you not do the algebra?

- Calculus -
**Anonymous**, Wednesday, June 8, 2011 at 3:35pm
just simplify what bob put you'll get D!

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