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Calculus

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A car passes by a certain point at time t = 0 hours heading east at 40 miles per hour. At t = 1 hour another car passes by the same point heading north at 50 miles per hour. What is the functiuonthat equals the distance between the two cars?

  • Calculus - ,

    distance= sqrt[(40t)^2+(50(t-1))^2 ]

    check my thinking.

  • Calculus - ,

    The answer has to be one of the following:
    a. L=90t-50
    b. L= sqrt(4100t)
    c. L= sqrt(4100t^2 +5000t +2500)
    d. L= sqrt(4100t^2-5000t + 2500)
    e. L= sqrt(90t-50)

  • Calculus - ,

    And, it is one of those. Can you not do the algebra?

  • Calculus - ,

    just simplify what bob put you'll get D!

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