Posted by Liz on Wednesday, June 8, 2011 at 3:00pm.
A car passes by a certain point at time t = 0 hours heading east at 40 miles per hour. At t = 1 hour another car passes by the same point heading north at 50 miles per hour. What is the functiuonthat equals the distance between the two cars?

Calculus  bobpursley, Wednesday, June 8, 2011 at 3:05pm
distance= sqrt[(40t)^2+(50(t1))^2 ]
check my thinking.

Calculus  Liz, Wednesday, June 8, 2011 at 3:21pm
The answer has to be one of the following:
a. L=90t50
b. L= sqrt(4100t)
c. L= sqrt(4100t^2 +5000t +2500)
d. L= sqrt(4100t^25000t + 2500)
e. L= sqrt(90t50)

Calculus  bobpursley, Wednesday, June 8, 2011 at 3:35pm
And, it is one of those. Can you not do the algebra?

Calculus  Anonymous, Wednesday, June 8, 2011 at 3:35pm
just simplify what bob put you'll get D!
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