Monday

July 28, 2014

July 28, 2014

Posted by **LA** on Wednesday, June 8, 2011 at 4:07am.

10y^7 +26y^6 -12y^5

- PreCal -
**Reiny**, Wednesday, June 8, 2011 at 7:56am10y^7 +26y^6 -12y^5

= 2y^5(5y^2 + 13y - 6)

= 2y^5(5y - 2)(y + 3)

- PreCal -
**Anonymous**, Monday, June 4, 2012 at 12:34am,l

**Related Questions**

algebra 2..again - 2y^3-10y^2+12y...need to factor again..i got to the second ...

Math - factor completely 3y^3 - 12y

algebra 1 - completely factor: 10y^2 -90

Algebra - Factor completely: x^10y^3 – 4x^9y^2 – 21x^8y

algebra 1 [fractions] - 8y^4+10y^3+12y+15 ----------------- 4y+5 divide then ...

math - factor the polynomial completely... 3x-15+2xy-10y

Algebra - Ok I got two I need help with : 1. Factor Completely 7x^2 + 49x + 42 I...

math help - 5x+10y +15z-15x+10y-5z+5x-10y-5z / (5x+10y+15z)-(15x+10y-5z)+(5x-10y...

precal - Hi I know is is probably basic but can anyone assist with the following...

Math - Correct the error in this equation: 6(2y+6)=4(9+3y) 12y+36=36+12y 12y=12y...