Homework Help: chemistry

Posted by Deb on Wednesday, June 8, 2011 at 2:02am.

determine half life of krypton-92 if only 6.0 millograms of an original 96.0 sample remains unchanged after 7.36 seconds

chemistry - DrBob222, Wednesday, June 8, 2011 at 2:12pm
ln(No/N) = kt
No = 96
N = 6
k = unknown
t = 7.36 seconds.
Then substitute k into the below equation.
k = 0.693/t_1/2 and solve for t_1/2.
chemistry - g, Thursday, January 12, 2012 at 9:57pm
1.84 seconds

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