What is the critical angle in flint glass when light passes from flint glass into air?
flint glass = 1.70
air = 1.0003
To calculate the critical angle when light passes from flint glass into air, we need to use Snell's Law, which states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indices of the two media.
The formula for Snell's Law is:
n1 * sin(theta1) = n2 * sin(theta2)
Given:
n1 (refractive index of flint glass) = 1.70
n2 (refractive index of air) = 1.0003
We want to find the critical angle, which is the angle of incidence when the angle of refraction becomes 90 degrees. In this case, sin(theta2) will be equal to 1.
Substituting the values into the formula, we have:
1.70 * sin(theta1) = 1.0003 * 1
Since sin(90 degrees) is equal to 1, we can rewrite the equation as:
1.70 * sin(theta1) = 1.0003
Now, to find the critical angle, we can rearrange the equation to solve for sin(theta1):
sin(theta1) = 1.0003 / 1.70
Using a scientific calculator, take the inverse sine of the above ratio to find the value of theta1 (angle of incidence). This will give us the critical angle at which light passes from flint glass into air.