Algebra
posted by Rachal on .
Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 4L, the pressure is 165 kPa(kilopascals). What is the volume when the pressure is 60 kPa?

".. the volume of a gas varies inversely with the pressure"
implies that
V =k/P, where k is a constant
given: when V=4, P = 165
4 = k/165
k = 660
so we have : V = 660/P
when P = 60
V = 660/60 = 11
or
the volume of a gas varies inversely with the pressure
V1/V2 = P2/P1
4/V2 = 60/165
60V2 = 660
V2 = 660/60 = 11