Homework Help: Chemistry

Posted by Vinny on Tuesday, June 7, 2011 at 7:29pm.

What volume of .300 M CaCl2 is needed to react completely with 40.00 Ml of .200 M H2PO4. according to the following equation

3 CaCl2 (aq) + 2 H3PO4 (aq)-> Ca3(po44)2 + 6 HCL (aq)

Chemistry - bobpursley, Tuesday, June 7, 2011 at 7:32pm
you need 3/2 moles of CaCl2 for each mole of H3PO4.

moles of phosphoric acid: .04*.2
moles of calcium chloride: 3/2 * .008

moles of calcium chloride= volume*.3

volume= (3/2 .008)/.3 liters
Chemistry - moata, Sunday, April 15, 2012 at 2:55am
If the 3 moles of Calcium Nitride was then dissolved in 2 L of liquid ammonium what would the molarity of the Calcium Nitride /ammonium solution be?

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