What is the molarity of a 37.50 mL sample of HNO3 solution that will completely react with a 23.70 of .0100 M NaOH?
Write the equation and balance it.
HNO3 + NaOH ==> NaNO3 + H2O
moles NaOH = M x L = ??
Using the coefficients in the balanced equation, convert moles NaOH to moles HNO3. Since the ratio is 1:1, that means moles NaOH = moles HNO3.
M HNO3 = moles HNO3/L HNO3.
thank you, I got it I think its .0632 M after dividing .00237m/.03750 L
I didn't find that. My calculator reads 0.00632 M.
To find the molarity of the HNO3 solution, we need to use the concept of stoichiometry and the balanced chemical equation between HNO3 and NaOH.
The balanced equation for the reaction between HNO3 and NaOH is:
HNO3 + NaOH → NaNO3 + H2O
According to the balanced equation, 1 mole of HNO3 reacts with 1 mole of NaOH to form 1 mole of NaNO3 and 1 mole of H2O.
We are given that 23.70 mL of 0.0100 M NaOH solution reacts with the HNO3. To solve for the molarity of the HNO3 solution, we can use the equation:
(moles of HNO3) = (volume of NaOH solution in liters) x (molarity of NaOH solution)
First, we need to convert the volume of NaOH solution from milliliters to liters:
(23.70 mL) x (1 L / 1000 mL) = 0.02370 L
Next, we can substitute the values into the equation:
(moles of HNO3) = (0.02370 L) x (0.0100 M) = 0.000237 moles of HNO3
Since 1 mole of HNO3 reacts with 1 mole of NaOH, the number of moles of HNO3 that will react is equal to the number of moles of NaOH used.
Now let's calculate the molarity of the HNO3 solution:
Molarity (M) = (moles of solute) / (volume of solution in liters)
We are given a 37.50 mL sample of the HNO3 solution, so we'll convert it to liters:
(37.50 mL) x (1 L / 1000 mL) = 0.03750 L
Substituting the values into the equation:
Molarity (M) = (0.000237 moles) / (0.03750 L) = 0.00632 M
Therefore, the molarity of the HNO3 solution is 0.00632 M.