Post a New Question

modern physics - relativity

posted by .

A photon of energy E collides with a stationary particle of rest mass m0 and is absorbed by it .

(A) what is the velocity of resulting composite particle ?

(B) What is the mass of the resulting composite particle ?

use conservasion of energy / momentum please show working

  • modern physics - relativity -

    A) You can find the velocity by cmputing the total energy and momentum. From:

    E = gamma m c^2


    P = gamma m v

    it follows that

    p/E = v/c^2

    The total energy is:

    E + m0 c^2

    The total momentum is the momentum of the photon, which is E/c. The total energy and momentum are conserved, so these are the energy and momentum of the particle after the photon has been absorbed. The velocity of that particle is thus:

    v = c^2 momentum/energy =

    c^2 E/c 1/(E + m0 c^2 ) =

    E c/(E + m0 c^2)

    The mass follows from the invariant:

    E^2 - p^2 c^2

    Fora system with eenrgy E and momentum p, this quantity has the same valyue in all frames. If you evaluate this in the rest frame then p = 0 and E = m c^2, so it is E^2 = m^2 c^4. The fact tha the quatity is invariant, means that it has this value in any frame. This means that given the enrgy and momentum of a system, you can compute the mass:

    m^2 = E^2/c^4 - p^2/c^2

    In this case, you find:

    m^2 = (E + m0 c^2)^2/c^4 - E^2/c^4 =

    2 m0 E/c^2 + m0^2

    So, the mass is:

    m = m0 sqrt[1 + 2 E/(m0 c^2)]

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question