Posted by Vince on Tuesday, June 7, 2011 at 2:39pm.
Write the equation of a hyperbola with a center at (5, 3), vertices at (5, 5) and (5, 1) and covertices at (11, 3) and (1, 3).

EASY MATH  Reiny, Tuesday, June 7, 2011 at 3:00pm
distance from centre (5,3) to vertex (5,1) is 2
so a = 2
distance from (5,3) to (1,3) is 6,
so b=6
equation:
(x+5)^2 / 4  (y+3)^2 / 36 = 1

THANK YOU REINY!  Vince, Tuesday, June 7, 2011 at 3:12pm
:)
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