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Posted by **Jessica** on Tuesday, June 7, 2011 at 11:19am.

- Math -
**MathMate**, Tuesday, June 7, 2011 at 11:40amTake out the obvious common factor xy:

(4x^3)y - 9xy^3

=xy(4x^2 - 9y^2)

and factor as difference of two squares

=xy((2x)²-(3y)²)

=xy(2x+3y)(2x-3y)

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