Posted by jacara on Tuesday, June 7, 2011 at 10:26am.
FInd the exact value pf the 6 trig function of alpha
Given: point (-2,-6) on the terminal side of the angle in standard position
- trig - Henry, Wednesday, June 8, 2011 at 2:59pm
X = -2-0 = -2.
Y = -6-0 = -6.
r = sqrt((-2)^2+(-6)^2) = sqrt40 =
sqrt(4*10) = 2sqrt10.
sinA = Y/r = -6/2sqrt10 = -3/sqrt10 =
cosA = X/r = -2 / 2sqrt10 =
-1 / sqrt10 = -sqrt10 / 10.
tanA = Y/X = -6/-2 = 3.
cscA = 1/sinA = 10 / -3sqrt10 =
10sqrt10 / -3*10 = 10sqrt10 / -30 =
sqrt10 / -3.
secA = 1/cosA = -3 / sqrt10 =
-3sqrt10 / 10.
cotA = 1/tanA = 1/3.
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