Posted by jacara on Tuesday, June 7, 2011 at 10:26am.
FInd the exact value pf the 6 trig function of alpha
Given: point (-2,-6) on the terminal side of the angle in standard position
- trig - Henry, Wednesday, June 8, 2011 at 2:59pm
X = -2-0 = -2.
Y = -6-0 = -6.
r = sqrt((-2)^2+(-6)^2) = sqrt40 =
sqrt(4*10) = 2sqrt10.
sinA = Y/r = -6/2sqrt10 = -3/sqrt10 =
cosA = X/r = -2 / 2sqrt10 =
-1 / sqrt10 = -sqrt10 / 10.
tanA = Y/X = -6/-2 = 3.
cscA = 1/sinA = 10 / -3sqrt10 =
10sqrt10 / -3*10 = 10sqrt10 / -30 =
sqrt10 / -3.
secA = 1/cosA = -3 / sqrt10 =
-3sqrt10 / 10.
cotA = 1/tanA = 1/3.
Answer This Question
More Related Questions
- trig - express 20sin theta + 4 cos theta as R sin(theta + alpha) R sin(theta + ...
- algebra - if sin alpha is 0.28° where 0° is less than or equal to alpha less ...
- trig - evaluate the following in exact form, where the angeles alpha and beta ...
- trig - Please find sin (alpha/2) and cos (alpha/2) sec alpha = 3, -pi/2 < ...
- precal - when solving for all solutions how do I work out this problem: cos4(...
- Trigonometry - Write cos(-83degrees) as a function of a positive angle Prove ...
- Trigonometry - Find the counterexample to shows that the equation sec (alpha) - ...
- MATH - knowledge : point (-3,-4)is on the terminal arm of an angel (alpha) in ...
- trigonometry - given that sin alpha/2 = 2/3, and that alpha/2 is in quadrant II...
- trig - Find sin (alpha/2) and cos (alpha/2) sin alpha = 3, -pi/2 < alpha <...