Posted by jacara on Tuesday, June 7, 2011 at 10:26am.
FInd the exact value pf the 6 trig function of alpha
Given: point (2,6) on the terminal side of the angle in standard position
sin alpha
cos alpha
tan alpha
sec alpha
csc alpha
cot alpha

trig  Henry, Wednesday, June 8, 2011 at 2:59pm
(0,0), (2,6).
X = 20 = 2.
Y = 60 = 6.
r = sqrt((2)^2+(6)^2) = sqrt40 =
sqrt(4*10) = 2sqrt10.
sinA = Y/r = 6/2sqrt10 = 3/sqrt10 =
3sqrt10/10.
cosA = X/r = 2 / 2sqrt10 =
1 / sqrt10 = sqrt10 / 10.
tanA = Y/X = 6/2 = 3.
cscA = 1/sinA = 10 / 3sqrt10 =
10sqrt10 / 3*10 = 10sqrt10 / 30 =
sqrt10 / 3.
secA = 1/cosA = 3 / sqrt10 =
3sqrt10 / 10.
cotA = 1/tanA = 1/3.
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