Saturday
March 28, 2015

Homework Help: Chemistry

Posted by Lance on Tuesday, June 7, 2011 at 8:24am.

Propane, C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would need to provide 383 kJ of heat.
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)
ΔH = −2043 kJ

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - Propane, C3H8, is a common fuel gas. Use the following to calculate...
chemistry - The complete combustion of propane, C3H8(g), is represented by the ...
Chem - Could someone please walk me through step by step on how to do this. ...
Chemistry - A small bottle of propane gas (C3H8) contains 400.0 grams of propane...
Chemistry Help!! - Propane(C3H8), the major component of LP game, is often used ...
Chemistry - For the following reaction, 5.20 grams of propane (C3H8) are allowed...
Chemistry - Propane (C3H8) burns according to the following balanced equation: ...
chemistry - What mass of propane (C3H8) is needed to produce 346g carbon dioxide...
chemistry question - What mass of propane (C3H8) is needed to produce 346 g ...
Chemistry - Consider the combustion of propane (C3H8) in the presence of oxygen...

Members