Homework Help: Chemistry

Posted by Lance on Tuesday, June 7, 2011 at 8:24am.

Propane, C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would need to provide 383 kJ of heat.
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)
ΔH = −2043 kJ

Chemistry - drwls, Tuesday, June 7, 2011 at 9:13am
That is 2043 kJ of heat release per mole of fuel. Each mole of propane has a mass of 3*12 + 8*1 = 44 grams.

You need (383/2043)*44 g of propane

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