Posted by D on Monday, June 6, 2011 at 3:11pm.
Given the quadrilateral ABCD with the following vertices A(4, 0), B(10, 0), C(10, 10), and D(0, 14), find its area.

geometry  Reiny, Monday, June 6, 2011 at 4:41pm
After you sketch it, it is easy to see that you can split the area up into 2 triangle and a square, whose areas are 28, 20 and 100 , for a total of 148
or
list the coordinates in a column, repeating the first point
4 0
10 0
10 10
0 14
4 0
the area is (1/2)( sum of downproducts  sum of upproducts)
 (1/2)(0+100+140+0 (0+0+056)
= (1/2(240 + 56) = 148
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