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posted by Robo on Monday, June 6, 2011 at 2:07pm.

Find the value of c such that the point (4,2) lies in the graph of f(x)= cx^2+3x-4.

F(x) = CX^2 + 3X - 4. Xv = -b/2a = -3 / 2c = 4, -3 / 2c = 4, c = -3/8.

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