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December 19, 2014

December 19, 2014

Posted by **math...** on Monday, June 6, 2011 at 1:46pm.

- mathematics -
**Damon**, Monday, June 6, 2011 at 2:20pmlet AB = x

then BC = 2x

then CE = 4x

angle B and angle C are right

AB/BC = BC/CE = 1/2

triangle ABC similar to triangle BCE

Call F intersection of BE and AC

Now angle EBC = FAB (similar triasngles)

Angle FCB = BEC (also same similar triangles)

BUT those angles add to 90 degrees (two angles in right triangle)

so

angle BFC = 90 degrees

- mathematics -
**Anonymous**, Monday, June 6, 2011 at 2:23pmthanks for ur help..

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