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November 26, 2014

November 26, 2014

Posted by **CheezyReezy** on Monday, June 6, 2011 at 1:44pm.

ln((x^2 – 1)/(x^2 – 6x + 8)) – ln((x+1)/(x+2))

- Math - Write expression as single logarithm -
**Damon**, Monday, June 6, 2011 at 1:56pmln((x^2 – 1)/(x^2 – 6x + 8)) – ln((x+1)/(x+2))

when you subtract the logs, you divide the arguments

ln (x+1)(x-1) / [(x+1)(x-1)((x-4)(x-2)]

ln 1/[(x-4)(x-2)]

ln [ (x-4)(x-2) ]^-1

-ln [ (x-4)(x-2)]

- Math - Write expression as single logarithm -
**Anonymous**, Tuesday, May 14, 2013 at 2:20pm6logb v+2logb t

- Math - Write expression as single logarithm -
**Bob**, Sunday, May 19, 2013 at 4:07pm12logb^2vt

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