Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Math
show that the equation x^2+2xy+y^2+x+y-2=0 rebresent two paralil straight lines and find the equation of those two lines
1 answer
x^2+2xy+y^2+x+y-2=(x+y+2)(x+y-1)
y=-x-2
y=-x+1
You can
ask a new question
or
answer this question
.
Similar Questions
show that the equation x^2+2xy+y^2+x+y-2=0 rebresent two paralil lines and find the equations of thos lines
Top answer:
x^2+2xy+y^2+x+y-2=0 Decomposition: (x+y-1)(x+y+2)=0 Expresion has zeros when: x+y-1=0 and (x+y+2)=0
Read more.
Consider the closed curve in the day plane:
2x^2-2xy+y^3=14 a) show that dy/dx=2y-4x/3y^2-2x (I got this part) b) find equation
Top answer:
Consider the closed curve in the xy plane: 2x^2-2xy+y^3=14 a) show that dy/dx=2y-4x/3y^2-2x (I got
Read more.
find the equation of all horizontal tangents to the curve y^2 = (x^2+4)/x, if any exist
this is what I have so far: xy^2= x^2+4
Top answer:
you know that y^2 = (x^2+4)/x, so just plug that in and solve for x.
Read more.
dy/dx= (y^2 -1)/x
1. Give the general equation of the curves that satisfy this equation. 2. Show that the straight lines y=1 and
Top answer:
To show that y = 1 and y = -1 are solutions to the given differential equation, you can substitute
Read more.
Find the equation of ALL horizontal tangents to the curve y^2=x^2+4/x, if any exists.
My work: Derivative- First I multiply
Top answer:
y^2 = x^2 + 4/x 2y y' = 2x - 4/x^2 y' = (2x^3-4)/x^2 * 1/2y = (x^3-2) / x^2y Now as long as y≠0,
Read more.
Simplify (2xy^2+3)((2xy^2)^2-(2xy^2)(3)+(3)^2)
This reminds me of (U+a)(U^2- aU + a^2). When mulipltiplied out, one gets a cubic
Top answer:
Yes, the formula for factoring the sum of two cubes is: a^3 + b^3 = (a + b)(a^2 - ab + b^2). In this
Read more.
The equation x^2 y+2xy^3=8defines y as a function of x,y=f(x), near x=2, y=1.
a) Find dy/dx. b) Now, find the slope of the curve
Top answer:
differentiate implicitly, x^2 + 2xy^3 = 8 2x + 2x(3y^2)dy/dx + 2(y^3) = 0 solve for dy/dx, then for
Read more.
The equation of a straight line ,l1 is 2y+8x-10.another line,l2 cuts l1 at right angles such that the point of intersection of
Top answer:
We can begin by finding the slope of the first line, l1. To do this, we can rearrange the equation
Read more.
dy/dx= (y^2 -1)/x
1. Give the general equation of the curves that satisfy this equation. 2. Show that the straight lines y=1 and
Top answer:
kuivrf mtqi sgbejy cism wdambueky ecbp hxcy
Read more.
The graph of the equation x2 − xy + y2 = 9 is an ellipse. Find the lines tangent to this curve at the two points where it
Top answer:
x^2 - xy + y^2 = 9 2x - x dy/dx - y + 2y dy/dx = 0 dy/dx(2y - x) = y - 2x dy/dx = (y-2x)/(2y-x) at
Read more.
Related Questions
Consider the equation x^2y+3y^3=24
Find dy/dx I got -2xy/x^2+9y^2 The next question is Determine the points, if any where the
the straight L has gradient 3 and passes through the point A(-6,4).
a) find an equation for L in the form y=mx+c b) straight line
ABCD is a rectangle. A is the point (0,1). c is the point (0,6) the equation of the straight line through A and B is y=2x+1.
(a)F
A curve has implicit equation x^2-2xy+4y^2=12
a)find the expression for dy/dx in terms of y and x. hence determine the
the straight line l1 has equation y=2x+3
the straight line l2 is parallel to l1 l2 passes through the point (3,2) find an
Consider the equation:
x^2 - 2xy + 4y^2 = 64 Write an expression of the slope of the curve at any point. (y^p)= y prime My work
Use implicit differentiation to find the equation of the tangent line to the curve xy^3+2xy=9 at the point (31). The equation of
let y be the function of x defined implicitly by the equation x^2 -2xy +2y^4=1. find the value of x where y obtains its maximum
Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
x2 + 2xy − y2 + x = 17,
The equation y=6x+6 describes the relationship between quantities x and y. Are the quantities in a proportional relationship?(1