Monday

September 22, 2014

September 22, 2014

Posted by **Eric** on Monday, June 6, 2011 at 11:12am.

- Statistics -
**MathGuru**, Monday, June 6, 2011 at 7:35pmTry this formula:

n = [(z-value)^2 * p * q]/E^2

= [(1.96)^2 * .7 * .3]/.06^2

= ? (round to the next highest whole number)

I'll let you finish the calculation.

Note: n = sample size needed. Use .7 for p and .3 for q (q = 1 - p). E = maximum error, which is .06 and z-value is 1.96.

I hope this helps.

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