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July 30, 2014

July 30, 2014

Posted by **JAE92** on Sunday, June 5, 2011 at 11:58pm.

Integrate [(x^2+5)/(x^3-x^2+x+3)]dx.

Thank you very much.

- Calculus AB -
**Mgraph**, Monday, June 6, 2011 at 12:14amx^3-x^2+x+3=(x+1)(x^2-2x+3)

(x^2+5)/(x^3-x^2+x+3)=

=A/(x+1)+(Bx+C)/(x^2-2x+3)

A(x^2-2x+3)+(Bx+C)(x+1)=x^2+5

A+B=1

-2A+B+C=0

3A+C=5

Find A,B,C

- Calculus AB -
**Bosnian**, Monday, June 6, 2011 at 12:35amIn google type:

wolfram alpha

When you see list of results click on:

Wolfram Alpha:Computational Knoweledge Engine

When page be open in rectangle type:

(x^2+5)/(x^3-x^2+x+3) and click option =

After few secons you will see all about that function.

Now click option:

Partial fraction expansion: Show steps

Now in wolfram alpha rectangle type:

2/(x^2-2x+3)+1/(x+1)

and click option =

When you see results clic option:

Indefinite integral: Show steps

- Calculus AB -
**JAE92**, Monday, June 6, 2011 at 12:49amThank you very much.

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