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A 1.5 uF capacitor is connected to a 9.0 V battery. Use PE=1/2C(change in V)^2 to find the energy stored in the capacitor.

  • Physics -

    C = 1.5*10^-6 farads
    V = 9.0 volts

    You have the formula. Do the calculation.

    The answer, (1/2)CV^2, will be in joules

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