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calculus

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given the functions f(x) = sqrt x+1 and g(x) = 6x+a in the xy coordinate plane, y= f[g(x)] passes through the point (3,5) . what is the value of a ?

  • calculus - ,

    I somehow think you meant
    f(x) = √(x+1)

    then f(g(x)) = √((6x+a) + 1)
    if (3,5) lies on it

    5 = √(18+a + 1)
    25 = a + 19
    a = 6

    If you meant f(x) = √x + 1
    then follow the same steps as above.

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