Posted by Taylor on Sunday, June 5, 2011 at 5:19pm.
Find the average rate of change of the function over the given interval. You must reduce and simplify your answer, if possible.
a. f(x)=cot x, [pi/6, pi/2]
b. f(theta)= 2 + cos (theta), [pi, 0]

calculus  MathMate, Sunday, June 5, 2011 at 6:04pm
I'll tackle the first one. The second one will be left for you as an exercise.
f(x)=cot x, [pi/6, pi/2]
To find the average rate of change over the interval, we divide the definite integral by the interval, namely:
Δf(x)/Δx
=∫f(x)dx / (π/2π/6)
=∫cot(x)dx / (π/3)
=[ln(sin(x))] /(π/3)
=[0ln(sin(π/6)]/(π/3)
=ln(2)/π/3
=3ln(2)/π
Answer This Question
Related Questions
 Trigonometry  I don't understand how I'm supposed set the problem up or what ...
 Precalculus  Circle O below has radius 1. Eight segment lengths are labeled ...
 Pre Calculus.  Can someone check my answers please!!! Simplify (tan ^2 theta ...
 Calculus  sec theta 5 need to find cos theta cot theta cot (90theta) sin theta...
 Algebra II  Multiple Choice Which expression is NOT equivalent to 1? (theta) ...
 Algebra II  Which of the following expressions are not equal to 1? A) sin^2 ...
 Precalculus check answers help!  1.) Find an expression equivalent to sec theta...
 Precalculus check answers help!  1.) Find an expression equivalent to sec theta...
 algebra  Can someone please help me do this problem? That would be great! ...
 Calculus  I wanted to confirm that I solved these problems correctly (we had to...
More Related Questions