mathematics
posted by me on .
Three times the reciprocal of the sum of two consecutive odd integers is 3/20. Find the two consecutive off integers.

Let 2n1 be the smaller odd integer, then
2n+1 is the larger.
Given
3/(2n1 + 2n+1)=3/20
3/(4n)=3/20
4n=20
n=5
The integers are 2*51=9 and 2*5+1=11.