Posted by **saud** on Sunday, June 5, 2011 at 11:38am.

Find the volume of the solid obtained by rotating the region under the graph of the function f(x)=x^8/9 about the x-axis over the interval [1,2].

- calculus II -
**saud**, Sunday, June 5, 2011 at 11:45am
Find the volume of the solid obtained by rotating the region under the graph of the function f(x)=(2)/(x+1) about the x-axis over the interval [0,4].

- calculus II -
**saud**, Sunday, June 5, 2011 at 11:46am
Find the volume of the solid obtained by rotating the region under the graph of the function f(x)=e^x about the x-axis over the interval [0,2].

- calculus II -
**Reiny**, Sunday, June 5, 2011 at 1:38pm
is that f(x) = x^(8/9) or f(x) = (x^8)/9

is will assume the latter.

Volume = π[integral) (x^16)/81 dx from 1 to 2

= π[x^17)/(17(81)) ] from 1 to 2

= π(2^17/(17(81)) - 1/(17(81))

= ....

- calculus II -
**Reiny**, Sunday, June 5, 2011 at 1:45pm
second one:

volume = π[integral] 4/(x+1)^2 from 0 to 2

= π((-4/(x+1)) from 0 to 2

= π(-4/3 - (-4/1)

= ....

third one:

you try it, the integral of (e^x)^2 is (1/2)e^(2x)

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