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December 20, 2014

December 20, 2014

Posted by **Jaden** on Saturday, June 4, 2011 at 11:38am.

3x+6 x^2-4

----- divided by -----

4x+12 x-3

- algebra -
**Jai**, Saturday, June 4, 2011 at 12:27pm(3x+6)/(4x+12) / (x^2 - 4)/(x-3)

first, to divide, we get the reciprocal of the divisor (or the second term/ term at the right) and the operation will be multiplication. reciprocal is just interchanging the numerator and denominator terms. thus,

(3x+6)/(4x+12) * (x-3)/(x^2 - 4)

factoring out each term,

[3(x+2)]/[4(x+3)] * (x-3)/[(x-2)(x+2)]

we can cancel out x+2:

[3(x-3)]/[4(x+3)(x-2)] or

(3x - 9)/(4x^2 + 4x - 24)

hope this helps~ :)

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