Homework Help: Trigonometry

Posted by Help needed! on Friday, June 3, 2011 at 12:04am.

Find all solutions on the interval (0,2pi):

2-2cos^2=sinx+1

Trigonometry - Reiny, Friday, June 3, 2011 at 7:07am
2 - 2(1-sin^2x) - sinx - 1 = 0
2sin^2x - sinx -1 = 0
(2sinx + 1 )(sinx-1) = 0
sinx = -1/2 or sinx = 1

x = 210° or 330° or 90°
or
x = 7π/6 , 11π/6, or π/2
Trigonometry - sunny, Wednesday, August 8, 2012 at 2:43pm
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