Posted by **Lsat** on Thursday, June 2, 2011 at 9:41pm.

Find all solutions of the equation on the interval [0,2pi):

Tan^2x=1-secx

- Trig -
**Bosnian**, Thursday, June 2, 2011 at 11:12pm
In google type:

wolfram alpha

When you see lis of results click on:

Wolfram Alpha:Computational Knowledge Engine

When page be open in rectangle type:

solve tan^2(x)=1-sec(x)

and click option =

After few secons you will see result.

Then clic option Show steps

- Trig -
**Bosnian**, Thursday, June 2, 2011 at 11:30pm
Remark:

When you see step

Simplify trigonometric functions:

If we know that:

tan^2(x)=sec^2(x)-1

tan^2(x)+sec^2(x)-1=0 becomes:

sec^2(x)-1+sec(x)-1=0

- Trig -
**Reiny**, Thursday, June 2, 2011 at 11:31pm
sec^2 x - 1= 1 - secx

sec^2 x + sec x - 2 = 0

(secx + 2)(secx -1) = 0

secx = -2 or secx = 1

cosx = -1/2 or cosx = 1

x = 120° or x = 240° or x = 0 or x = 360°

x = 0, 2π/3 , 4π/3, 2π

- Trig -
**Lsat**, Thursday, June 2, 2011 at 11:51pm
Thank you!

- algebra -
**shieda**, Wednesday, January 25, 2012 at 10:57pm
find all solutions to the equation 2x^3+12x^2+50x=0

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