If 10 grams of aniline are allowed to react with excess aceticanhydride what is the theoretical yield of acetanilide in moles?grams?

please explain

Here is a worked example of a stoichiometry problem. Just follow the steps.

http://www.jiskha.com/science/chemistry/stoichiometry.html

C6H5NH2 + (CH3CO)2O = C6H5NHCOCH3

1 mole 1 mole 1 mole
10g
mol wt of aniline 12x6 + 1x5 + 1x14+1x2=93
no of moles of aniline = wt/ mol wt
= 10/93=0.1075moles
1 mole aniline can gice 1 mole acetanilide
0.1075 mole can give = 0.1075mole
wt of acetanilide= no mole xmol wt of acetanilide
mol wt of acetanilide 6x12+5+14+1+12+16+12+3= 135
wt of acetanilide= 0.1075 x 135
=14.51 g

To determine the theoretical yield of acetanilide in moles and grams, we need to start by balancing the chemical equation for the reaction:

C6H7N + (CH3CO)2O → C8H9NO + CH3COOH

From the balanced equation, we can see that the molar ratio between aniline (C6H7N) and acetanilide (C8H9NO) is 1:1.

Step 1: Convert the mass of aniline to moles.
Given that the mass of aniline is 10 grams, we can calculate the number of moles using its molar mass. The molar mass of aniline is 93.13 g/mol.

Number of moles = mass / molar mass
Number of moles = 10 g / 93.13 g/mol
Number of moles = 0.1073 mol

Step 2: Determine the theoretical yield of acetanilide in moles.
Since the molar ratio between aniline and acetanilide is 1:1, the number of moles of acetanilide will be the same as the number of moles of aniline.

Theoretical yield of acetanilide in moles = 0.1073 mol

Step 3: Convert the theoretical yield of acetanilide to grams.
To calculate the theoretical yield of acetanilide in grams, we use its molar mass. The molar mass of acetanilide is 135.17 g/mol.

Mass = number of moles x molar mass
Mass = 0.1073 mol x 135.17 g/mol
Mass = 14.53 grams

Therefore, the theoretical yield of acetanilide is 0.1073 moles and 14.53 grams.

To determine the theoretical yield of acetanilide in moles, you need to use the stoichiometry of the balanced chemical equation for the reaction between aniline and acetic anhydride.

The balanced chemical equation for the reaction is:
C6H5NH2 + (CH3CO)2O -> C6H5NHCOCH3 + CH3COOH

From the equation, you can see that the molar ratio between aniline and acetanilide is 1:1. This means that for every 1 mole of aniline, you will obtain 1 mole of acetanilide.

Given that you have 10 grams of aniline, you need to convert this mass into moles. To do this, you will need the molar mass of aniline, which is 93.13 g/mol. Divide the mass by the molar mass to get the number of moles:

moles of aniline = mass of aniline / molar mass of aniline
moles of aniline = 10 g / 93.13 g/mol = 0.1073 mol

Since the molar ratio between aniline and acetanilide is 1:1, the number of moles of acetanilide will be the same as the number of moles of aniline:

moles of acetanilide = moles of aniline = 0.1073 mol

Finally, if you want to calculate the theoretical yield of acetanilide in grams, you need to use the molar mass of acetanilide, which is 135.17 g/mol. Multiply the number of moles of acetanilide by the molar mass to get the mass:

mass of acetanilide = moles of acetanilide * molar mass of acetanilide
mass of acetanilide = 0.1073 mol * 135.17 g/mol = 14.50 g

Therefore, the theoretical yield of acetanilide is 14.50 grams.