Posted by CheezyReezy on Wednesday, June 1, 2011 at 10:01pm.
trying a few factors of 14, I found
f(-1) = 0 and f(2) = 0
so after 2 consecutive synthetic divisions, that left me with
(x+1)(x-2)((x^2 - 6x - 7)
= (x+1)(x-2)(x+1)(x-7)
so we have a double zero at x=-1
and two more zeros at 2 and 7
I just wasted my valuable time doing the above question before noticing that your same question had already been answered.
Do not repost the same question without checking if it has been answered.
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