Posted by **CheezyReezy** on Wednesday, June 1, 2011 at 9:03pm.

Solve the following equation in the real number system. Please show all of your work.

x^4 + 6x^3 + x^2 - 24x - 20 = 0

Help!!!!

- Math - Real number system -
**Mgraph**, Wednesday, June 1, 2011 at 10:17pm
Let f(x)=x^4+6x^3+x^2-24x-20

Real roots are looking for among

+-1,+-2,+-4,+-5,+-10,+-20

f(-1)=1-6+1+24-20=0

Divide f(x) by (x+1):

f(x)=(x+1)(x^3+5x^2-4x-20)

Let g(x)=x^3+5x^2-4x-20

g(-5)=-125+125+20-20=0

Divide g(x) by (x+5):

g(x)=(x+5)(x^2-4)

f(x)=(x+1)(x+5)(x+2)(x-2)

- Math - Real number system -
**billy**, Sunday, September 23, 2012 at 8:57pm
what is 2/5 in the real number system

## Answer this Question

## Related Questions

- calculus - Solve the equation in the real number system X^4+11x^3+24x^2-23x+35=0...
- college algebra--need help please!! - solve the equation in the real number ...
- college algebra - Solve the following equation in the real number system. Please...
- calculus-can someone please help me with this ques - I have two questions if ...
- Math - Solve the following equation in the complex number system. Please show ...
- math - The number of real solutions to the system of equations y=2sin(x^2) and y...
- college algebra - Solve the following equation in the complex number system. ...
- pre calculus - solve the following equation in the complex number system Please ...
- college alegebra - solve the following equation in the real number system 3x^3...
- Math - did i work these problems right if not could some one show me how to work...