Posted by **CheezyReezy** on Wednesday, June 1, 2011 at 9:03pm.

Solve the following equation in the real number system. Please show all of your work.

x^4 + 6x^3 + x^2 - 24x - 20 = 0

Help!!!!

- Math - Real number system -
**Mgraph**, Wednesday, June 1, 2011 at 10:17pm
Let f(x)=x^4+6x^3+x^2-24x-20

Real roots are looking for among

+-1,+-2,+-4,+-5,+-10,+-20

f(-1)=1-6+1+24-20=0

Divide f(x) by (x+1):

f(x)=(x+1)(x^3+5x^2-4x-20)

Let g(x)=x^3+5x^2-4x-20

g(-5)=-125+125+20-20=0

Divide g(x) by (x+5):

g(x)=(x+5)(x^2-4)

f(x)=(x+1)(x+5)(x+2)(x-2)

- Math - Real number system -
**billy**, Sunday, September 23, 2012 at 8:57pm
what is 2/5 in the real number system

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