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March 28, 2017

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The density of aluminum is 2.70g/cm3. If a cube of aluminum weighs 13.5 grams whatis the length of the edge of the cube. I need help with the formula to figure this one out.

  • Chemistry - ,

    mass = volume x density
    Solve for volume.
    Then, since this is a cube, the length, width, and height are equal. So
    volume = L x W x H but since L = W = H, then
    volume = L x L x L. Solve for L.

  • Chemistry - ,

    Hello Dr Bob,, I am still a little confused is this what it will look like 13.5/2.70=5 then take 5*5*5=125

  • Chemistry - ,

    Close but no cigar.
    Volume = mass/density = 13.5/2.7 = 5.0 cc whis is ok to this point. Now,
    volume = L x L x L
    5 = L x L x L
    5 = L3; therefore,
    L = cube root 5 OR

    L = 51/3
    (On your calculator, enter 5, then punch the y^x button, and type in .33333 (which is 1/3) and = to find the answer of 1.70997 which rounds to 1.71 cm to three significant figures.

  • Chemistry - ,

    Thank you DR Bob

  • Chemistry - ,

    81 g

  • Chemistry - ,

    Aluminum has a density of 2.7 g/mL. What is the volume of an aluminum Cube that has a mass of 12.7 grams

  • Chemistry - ,

    mass = volume x density
    since this is a cube the length,width and height are
    equal so volume =L ×W×H but since L=W=H
    volume = mass/density
    = 12,7÷2,7

    = 4,703703704
    4,703703704 = L^3
    L = 1,675508565cm

  • Chemistry - ,

    I dont know

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