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January 27, 2015

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Posted by **nina** on Wednesday, June 1, 2011 at 5:20pm.

36x^3-33x^2-33x-6/9x+3

- algebra 2 -
**MathMate**, Wednesday, June 1, 2011 at 11:01pmWith parentheses properly inserted, it should read:

(36x^3-33x^2-33x-6)/(9x+3)

Try factorizing both numerator and denominator and cancel common factors, if possible:

(36x^3-33x^2-33x-6)/(9x+3)

=3(3x+1)(4x^2-5x-2)/3(3x+1)

=4x^2-5x-2

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